hero of Y

indienova.com/steam/game/3523000

Hero of Y is an RPG centered on the growth of a hero……eroded by evil forces in a chaotic world.Hero of Y……and allies, and ultimately grow into the “Hero of Y

干掉敌舰(Shmoup)

indienova.com/game/shmoup

开发:y-zo studio。发行:y-zo studio。发行日期:2023-05-16

Fantasya Final Definitiva REMAKE

indienova.com/steam/game/656120

década atrás, agora reunidos em uma única compilação……objetivo na vida (exceto ficar ainda mais bêbado).O……seu senso de moral e justiça no entanto, o levam a

Battle Pass – Y9S2 – FOR HONOR

indienova.com/steam/game/3793370

仅在 Y9S2 期间推出。荷耳克斯失落的秘宝再度现世。……如果你已经拥有 Y9S2 战斗同捆包,《荣耀战魂》Y9S2 战斗通行证就不会为游戏提供任何新的内容。……Y9S2 战斗通行证开放日期截止至 2025 年 9 月 9 日,不可退款

小玩意:原型(A Bibelot: Prototo)

indienova.com/game/a-bibelot-prototo

开发:y-zo studio。发行:y-zo studio。Prototo

赛博甜心:夏日约会(CyberHoney: Fashion - Summer Swimwear)

indienova.com/game/cyberhoney-fashion-summer-swimwear

解锁后可获得西蒙·海亚时装-夏日情、李逍儿时装-夏日情、神乐时装-夏日情、尤利安娜时装-夏日

clatterrr:游戏常见寻路算法可视化

indienova.com/u/clatterrr/blogread/24265

假设第一个点的x坐标是x1,y坐标是y1,第二个点的x坐标是x2,y坐标是y2。……y1)*(y2-y1))或是这样写:sqrt用于开平方根。……于是有些人推荐去掉这个开平方根的步骤,直接把((x2-x1)*(x2-x1)+(y2-y1)*(y2-

游戏常见寻路算法可视化

indienova.com/indie-game-development/pathfinding-visualization/

假设第一个点的 x 坐标是 x1,y 坐标是 y1,第二个点的 x 坐标是 x2,y 坐标是 y2。……y1)*(y2-y1))或是这样写:sqrt 用于开平方根。……于是有些人推荐去掉这个开平方根的步骤,直接把 ((x2-x1)*(x2-x1)+(y2-y1)*(y2

cfan_yjr:学习制作游戏--单屏平台游戏--主角的动作控制和重力的建立

indienova.com/u/cfanyjr/blogread/26926

sprite_index=spr_player_idle;}if(place_meeting(x+hsp,y,……我们需要修改主角的代码,在step事件里,增加如下代码if(place_meeting(x+hsp,y,……{grounded=false;}y+=vsp;在游戏房间里重新设置一下界面,四周围上一圈墙

好莱坞大亨 4(Hollywood Mogul 4)

indienova.com/steam/game/3536760

make a $300 million sci-fi epic right off the bat.o……definitive Comic Book Super Hero source database.o……Plus a heap of points on the back end.o HM4 Talent

版本:Early Access


总页数:50


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