Redactionary

indienova.com/game/redactionary

Redactionary is a free, web-based, competitive party word……who will have pre-written a description of a secret word……, to help the Decoder guess what the word is.Everyone

Super Word Games 10,000

indienova.com/game/super-word-games-10000

Super Word Games 10,000 it's a collection of words……games divided in: Word Search, Quickie Crosswords,……Word Scramble and Hangman Games.

Word Explorer!

indienova.com/game/word-explorer

It's a word game, it's a puzzle game, it's Word Explorer……levels and thousands of hidden words with this hidden word

【中文字幕】如何做更少的事让你的独立游戏变得更好?

indienova.com/indie-game-development/how-to-make-your-indie-game-better-by-doing-less/

几个月前,我阅读了格雷戈·麦吉沃恩的《精要主义》,这本书很好地诠释了“少就是多”这个概念。……在这个视频,我想要分享一些让我产生共鸣的观点,这些观点同样适用于独立游戏的开发过程。……在这个视频,我想要分享一些让我产生共鸣的观点,这些观点同样适用于独立游戏的开发过程

小组帖子:[团队招募]UE5狄拉克之海PvPvE多人竞技游戏招募玩家社群运营

indienova.com/groups/post/102449

正式招募全职玩家社群运营工作职责负责国内外各社交媒体的内容定期生产和发布;搭建和维护Discord社区,微群……Twitter 社区运营&增长和工具使用经验,活跃社区氛围,提升社区凝聚力;优秀的英文口语、写作、阅读能力……短视频运营,直播或Up主经验优先;简历投递:tiantian20007@gmail.com项目负责人微

小组帖子:视觉小说招募

indienova.com/groups/post/103785

A:已经完成了初步的情节设计与人物设定,有兴趣可以加我微信阅读我创作的小说原型。Q:如何加入该社团?……A:添加微:GenHaoShiEr12或QQ群:946747852,联系主创,你将获得展示自己和一同将点子变成现实的机会

小组帖子:视觉小说招募

indienova.com/groups/post/103786

A:已经完成了初步的情节设计与人物设定,有兴趣可以加我微信阅读我创作的小说原型。Q:如何加入该社团?……A:添加微:GenHaoShiEr12或QQ群:946747852,联系主创,你将获得展示自己和一同将点子变成现实的机会

Pocket Pack: Words & Numbers

indienova.com/game/pocket-pack-words-and-numbers

Pack: Words & Numbers is a collection of popular word……variety of games such as: Anagrams, Sudoku, Kakuro, Word……Cubes and Word Guess.

Stretch Text: Find Proverb

indienova.com/game/stretch-text-find-proverb

Embark on a word adventure like no other!……Text: Find Proverb' challenges your perception and word……skills in a captivating twist on word puzzles.

Challenge ME : Word Puzzles

indienova.com/game/challenge-me-word-puzzles

Challenge Me: Word Puzzles is a compilation of seven……fun word based puzzles including Anagrams, Word Search

版本:Early Access


总页数:50


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